Question 112647This question is from textbook Algebra 1
: The perimeter of a rectanngle is 160ft. One fourth the length is the same as twice the width. Find the dimensions of the rectangle. This question is from textbook Algebra 1
You can put this solution on YOUR website! A) 2L+2w=160
B) L/4=2w
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B) 4L/4=4*2w
L=8w
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A) 2*8w+2w=160 Substitute 8w for L.
16w+2w=160
18w=160
18w/18=160/18
w=80/9
L=640/9
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Check:
2*80/9+2*640/9
=160/9+1280/9
=1440/9
=160
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Ed