SOLUTION: A waitress sold 14 ribeye steak dinners and 18 grilled salmon​ dinners, totaling ​$574.17 on a particular day. Another day she sold 20 ribeye steak dinners and 6 grille

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: A waitress sold 14 ribeye steak dinners and 18 grilled salmon​ dinners, totaling ​$574.17 on a particular day. Another day she sold 20 ribeye steak dinners and 6 grille      Log On

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Question 1126418: A waitress sold 14 ribeye steak dinners and 18 grilled salmon​ dinners, totaling ​$574.17 on a particular day. Another day she sold 20 ribeye steak dinners and 6 grilled salmon​ dinners, totaling ​$583.22. How much did each type of dinner​ cost?
Found 2 solutions by greenestamps, josgarithmetic:
Answer by greenestamps(13215) About Me  (Show Source):
You can put this solution on YOUR website!


It's even more impolite to submit an unsolvable problem twice....

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If you "submitted the problem correctly", then the problem is flawed.

The price of each kind of meal has to be a whole number in dollars and cents; solving the pair of equations gives answers that are not.

Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
r, price of ribeye steak dinner
p, price of the fish dinner

system%2814r%2B18p=574.17%2C20r%2B6p=583.22%29

system%2814r%2B18p=574.17%2C60r%2B18p=1749.66%29

46r=1175.49

highlight%28r=25.55%29--------this was rounded to the nearest whole cent.

You can find p any way you want to.


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A well made problem of this kind should be expected to give whole numbered cents results for the prices (dollars, made of 100 equal parts).