SOLUTION: a chemist wants to mix a 22% acid solutions witha 50% acid solution to get 28 L of 30% solution. How many liters of the 22% solution and how many liters of the 50% solution should
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Question 1126270: a chemist wants to mix a 22% acid solutions witha 50% acid solution to get 28 L of 30% solution. How many liters of the 22% solution and how many liters of the 50% solution should be mixed Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! x liters of 22% and 28-x liters of 50%
.22x+.50(28-x)=28*0.3=8.4
.22x+14-.50x=8.4
-.28x=-5.6
x=20 liters of 22%, 4.4 liters of pure
28-x=8 liters of 50%, 4 liters of pure
