Question 1126215: How many cups of a
15
%
salt mixture and a
55
%
salt mixture should you mix to get
4
cups of a
45
%
salt mixture? Found 3 solutions by josgarithmetic, greenestamps, Alan3354:Answer by josgarithmetic(39614) (Show Source):
You are likely to get a response from one or more tutors here who will tell you the problem can't be solved because a 55% salt solution is physically impossible.
However, this is a math site and not a Chemistry site; clearly the intention of the problem was to give you practice in solving mixture problems. So let's do that.
First a solution by the traditional algebraic method.
let x = the number of cups of 15% solution
then 4-x = the number of cups of 55% solution
We want the 4 cups of mixture to be a 45% solution. So 15% of the x cups, plus 55% of the (4-x) cups, equals 45% of the 4 cups:
ANSWER: The mixture should use 1 cup of the 15% solution and 3 cups of the 55% solution.
Now a very different method which, as you will see, requires much less work.
(1) Think of the three percentages on a number line -- 15, 45, and 55.
(2) 45 is 3/4 of the way from 15 to 55. (do some simple mental arithmetic)
(3) That means 3/4 of the mixture must be the 55% solution.
(4) 3/4 of the total 4 cups is 3 cups.
ANSWER: 3 cups of the 55% solution, 1 cup of the 15% solution.
You can put this solution on YOUR website! Re: greenestamps' statement about 55% salt:
While the salt NaCl might not be soluble to 55%, other salts might be.
There are a lot of salts.
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Also, it wasn't specified salt in water.