SOLUTION: Find three consecutive odd integers such that the sum of twice the first and three times the second is 37 more than twice the third

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Question 1126101: Find three consecutive odd integers such that the sum of twice the first and three times the second is 37 more than twice the third
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
let the consecutive odd integers be
n, n+2, and n+4
+2n+%2B+3%2A%28+n%2B2+%29+=+2%2A%28n%2B4+%29+%2B+37+
+2n+%2B+3n+%2B+6+=+2n+%2B+8+%2B+37+
+5n+%2B+6+=+2n+%2B+45+
+3n+=+39+
+n+=+13+
and
+n+%2B+2+=+15+
+n+%2B+4+=+17+
the numbers are 13,15, and 17
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check:
+2%2A13+%2B+3%2A15+=+2%2A17+%2B+37+
+26+%2B+45+=+34+%2B+37+
+71+=+71+
OK