SOLUTION: A rock is thrown upward from a bridge that is 95 feet above a road. The rock reaches its maximum height above the road 0.87 seconds after it is thrown and contacts the road 3.36 se
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-> SOLUTION: A rock is thrown upward from a bridge that is 95 feet above a road. The rock reaches its maximum height above the road 0.87 seconds after it is thrown and contacts the road 3.36 se
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Question 1125995: A rock is thrown upward from a bridge that is 95 feet above a road. The rock reaches its maximum height above the road 0.87 seconds after it is thrown and contacts the road 3.36 seconds after it was thrown.
Write a function f that determines the rock's height above the road (in feet) in terms of the number of seconds t since the rock was thrown.
-f(t)= Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! With motion problems, the leading coefficient is -16 in English system of units
-16x^2+zx+95
the maximum height occurs at 0.87 seconds, so -b/2a is maximum height time
or -z/32=0.87, and z=27.84
Look at the function of -16x^2+27.84x+95
maximum height is 107.1 feet
It takes 2.59 seconds to fall 107.1 feet. That makes it 3.46 seconds before it hits.
