SOLUTION: Mabel paid $2.95 for a granola bar with dimes and quarters. She used 5 fewer quarters than dimes. How many dimes and quarters did she use to pay for the granola bar?
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-> SOLUTION: Mabel paid $2.95 for a granola bar with dimes and quarters. She used 5 fewer quarters than dimes. How many dimes and quarters did she use to pay for the granola bar?
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Question 1125964: Mabel paid $2.95 for a granola bar with dimes and quarters. She used 5 fewer quarters than dimes. How many dimes and quarters did she use to pay for the granola bar? Found 2 solutions by josgarithmetic, greenestamps:Answer by josgarithmetic(39617) (Show Source):
If an algebraic solution is not required, you can solve this problem easily with logical reasoning.
(1) Pay the portion of the cost represented by the 5 "extra" dimes. The remaining cost is $2.95-$0.50 = $2.45, made up of equal numbers of dimes and quarters.
(2) The value of 1 dime and 1 quarter is $0.35.
(3) The number of dimes and quarters now needed is $2.45/$0.35 = 7.