SOLUTION: 1 kilogram (kg) is about 2.2 times as heavy as 1 pound (lb). Suppose the function f determines Armando's weight (in lbs), f(t), given the number of days t since the beginning of 20

Algebra ->  Average -> SOLUTION: 1 kilogram (kg) is about 2.2 times as heavy as 1 pound (lb). Suppose the function f determines Armando's weight (in lbs), f(t), given the number of days t since the beginning of 20      Log On


   



Question 1125764: 1 kilogram (kg) is about 2.2 times as heavy as 1 pound (lb). Suppose the function f determines Armando's weight (in lbs), f(t), given the number of days t since the beginning of 2017. The function g determines Armando's weight (in kg), g(t), given the number of days t since the beginning of 2017.
-Suppose f(37)=193. What is the value of g(37)?
-Write a formula for g using the function f

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
if f(37) = 193, then g(37) would be equal to 193 / 2.2.

this is because the conversion factor is pounds = 2.2 * kilograms (approximately).

conversely, kilograms = pounds / 2.2 (approximately).

if you wrote g(t) to use f(t), then the function would be g(t) = f(t) / 2.2.

the weight would initially be calculated in pounds bhy f(t) and then be converted to kilograms by g(t).

in other words, the g(t) function would be dependent on the f(t) function.

in that case, you would have to use f(t) to calculate the weight in pounds first and then use g(t) to convert pounds to kilograms.

it' also hard to unerstand how you would calculator somebody's weight just based on the number of days elapsed in the year, but that's another issue.