SOLUTION: At the end of her shift a cashier has a total of $ 6.30 in dimes and quarters. There are 7 more dimes than quarters. How many of each of these coins does she have?

Algebra ->  Linear-equations -> SOLUTION: At the end of her shift a cashier has a total of $ 6.30 in dimes and quarters. There are 7 more dimes than quarters. How many of each of these coins does she have?      Log On


   



Question 1125700: At the end of her shift a cashier has a total of $ 6.30 in dimes and quarters. There are 7 more dimes than quarters. How many of each of these coins does she have?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +d+ = number of dimes
Let +q+ = number of quarters
———————
+d+=+q+%2B+7+
+10d+%2B+25q+=+630+ ( in cents )
————————————
+2d+%2B+5q+=+126+
By substitution:
+2%2A%28+q+%2B+7+%29+%2B+5q+=+126+
+2q+%2B+14+%2B+5q+=+126+
+7q+=+112+
+q+=+16+
And
+d+=+q+%2B+7+
+d+=+16+%2B+7+
+d+=+23+
She has 23 dimes and 16 quarters