Question 1125663: A programmer plans to develop a new software system. In planning for the operating system that he will use, he needs to estimate the percentage of computers that use a new operating system. How many computers must be surveyed in order to be 99% confident that his estimate is in error by no more than four percentage points question mark Complete parts (a) through (c) below.
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! for a one sample proportion, the SE for 0.995, or 99% confident, is
2.576*sqrt[p*(1-p)/n], and that equals 0.04
square both sides
6.636*0.5*0.5/n=0.0016, using 0.5 as the maximum sample size (most conservative). Multiply both sides by n, then divide both by 0.0016
n=1036.875 or 1037 computers
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