SOLUTION: The car company has found that the revenue from sales of sedans is a function of the unit price p,in dollars,that it charges.If the revenue R,in dollars,is R(p) = 1900p − 0

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Question 1125568: The car company has found that the revenue from sales of sedans is a function of the unit price p,in dollars,that it charges.If the revenue R,in dollars,is R(p) = 1900p − 0.5p2
(i) At what prices p is revenue zero? (ii) For what range of prices will revenue exceed $1.2 million?

Found 2 solutions by Alex.33, ikleyn:
Answer by Alex.33(110) About Me  (Show Source):
You can put this solution on YOUR website!
Assume expression "0.5p2" means 0.5p%5E2 (Otherwise please re-submit your question and clearify)
(i)R%28p%29=0, solve for p.
1900p-0.5p%5E2=0
hint: factor this stuff, take p out and you'll see the answer. More generally, apply the solution formula.


(ii)R%28p%29%3E=12000000, solve for the range of p.
1900p-0.5p%5E2%3E=1200000
hint: for quadratic inequalities, change that inequal sign to equal and solve. Then see what of the three ranges divided by the solutions will be the answer. You may use graph(or simply the properties of quadratic graphs) to see it comfortably.

And it'll be enough for you to work it out on your own!(And trust me, after that you'll find this kind of problems EASY next time)

Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
.
I'd like to make one notice, which does not relate to Math.


It relates to using terminology.


In this problem, you incorrectly use the term "revenue". 


The revenue is the product of the price and the number of items sold.


It can be equal to zero if and only if at least one of these factors is zero.


The number of items sold is zero ?   - Absurd.


The price is zero ?  - Absurd, too.


So, the formulation in the post MAKES NO SENSE due to incorrect using of terminology.


Actually, what you call a "revenue" is a "profit, instead.