SOLUTION: In triangle ABC, B is 15 less than two times A. If C is 3 degrees larger than B, find the three angles.
a+b+c=180
b=a.a-15
c=b+3
b= (a2-15)+3
b= (
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-> SOLUTION: In triangle ABC, B is 15 less than two times A. If C is 3 degrees larger than B, find the three angles.
a+b+c=180
b=a.a-15
c=b+3
b= (a2-15)+3
b= (
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Question 1125493: In triangle ABC, B is 15 less than two times A. If C is 3 degrees larger than B, find the three angles.
a+b+c=180
b=a.a-15
c=b+3
b= (a2-15)+3
b= ( Found 2 solutions by MathLover1, MathTherapy:Answer by MathLover1(20850) (Show Source):
You can put this solution on YOUR website! In triangle ABC, B is 15 less than two times A. If C is 3 degrees larger than B, find the three angles.
a+b+c=180
b=a.a-15
c=b+3
b= (a2-15)+3
b= (
Let angle A be A
Then angle B = 2A - 15
And, angle C = 2A - 15 + 3, or 2A - 12
As the 3 angles sum to 180o, we get: A + 2A - 15 + 2A - 12 = 180
5A = 207 Solve that for A, angle A's measurement.
Subtract 15 from TWICE A to get B's measurement.
Subtract 12 from TWICE A to get C's measurement.
That's it!! It's as SIMPLE as that!!