SOLUTION: I would be so happy if someone can help me work this out please.
Ina Crespo rowed 12 miles down the Habashabee River in 1.5 ​hours, but the return trip took her 4 hours. Fin
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-> SOLUTION: I would be so happy if someone can help me work this out please.
Ina Crespo rowed 12 miles down the Habashabee River in 1.5 ​hours, but the return trip took her 4 hours. Fin
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Question 1125421: I would be so happy if someone can help me work this out please.
Ina Crespo rowed 12 miles down the Habashabee River in 1.5 hours, but the return trip took her 4 hours. Find the rate Ina rows in still water and the rate of the current. Let x represent the rate Ina can row in still water and let y represent the rate of the current.
d=r•t
Downstream x+y
Upstream x−y
Ina can row ____mph in still water. Answer by ikleyn(52873) (Show Source):
Let x represent the rate Ina can row in still water and
let y represent the rate of the current.
Then her effective speed downstream is x+y miles per hour,
while her effective speed upstream is x-y miles per hour.
// It is first major point you need understand and use in this sort of problems.
Now, "speed" equation for boat floating downstream is
= u + v (1) (speed downstream = the distance divided by time downstream)
Next, "speed" equation for boat floating upstream is
= u - v (2) (speed upstream = the distance divided by time duptream)
// It is the second major point in solving such problems: you must understand and write these equation automatically !
Simplify equations (1) and (2)
u + v = 8 (3)
u - v = 3 (4)
Now add equations (3) and (4) to eliminate "v". You will get
2u = 8 + 3 = 13 ====> u = = 6.5.
Thus you just found the boat' speed in still water. It is 6.5 miles per hour.
Next, you can find the current rate from eq(4) v = 8 - u = 8 - 6.5 = 1.5 miles per hour.
Answer. The boat' speed in still water is 6.5 miles per hour.
The current speed is 1.5 miles per hour.
Solved. I advise you to make the check on your own.
After making the check, you will understand the problem and the solution MUCH better.
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It is a typical and standard Upstream and Downstream round trip word problem.