SOLUTION: Hello! Please help me answer this problem. I've gotten the answer but unsure if it's correct or not: A cyclist and a jogger set out at 6:00AM from the same point, headed in the

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: Hello! Please help me answer this problem. I've gotten the answer but unsure if it's correct or not: A cyclist and a jogger set out at 6:00AM from the same point, headed in the       Log On

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Question 1125417: Hello! Please help me answer this problem. I've gotten the answer but unsure if it's correct or not:
A cyclist and a jogger set out at 6:00AM from the same point, headed in the same direction. The average speed of the cyclist is twice the average speed of the jogger. In one hour, the cyclist is 7 km ahead of the jogger. What is the rate of the cyclist?
The answer I've gotten so far is 2.3333...

Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
jogger, r
cyclist, 2r
their speed of separation, r.

ONE hour, distance difference 7 km.

r%2A1=7, rate multiplied by time is distance.

highlight%28r=7%29--------speed of jogger

highlight%28highlight%2814%29%29-----------speed of cyclist