Question 1125413: I need help breaking this down, please, and thank you.
In a certain year, the average e-mail user sent or received 162 e-mails each day. The number of e-mails received was 6 more than thrice the number sent. How many were sent and how many were received each day?
For each day,
___e-mails were sent and
___e-mails were received.
Found 4 solutions by josgarithmetic, ikleyn, greenestamps, MathTherapy:
Answer by josgarithmetic(39615)   (Show Source):
Answer by ikleyn(52770)  (Show Source):
You can put this solution on YOUR website! .
Let x be the number of Emails sent.
Then the number of Emails received is (2x+6), according to the condition.
x + (2x+6) = 162.
x + 2x + 6 = 162
3x = 162 - 6 = 156 ====> x =  = 52.
Answer. 52 Emails were sent; 2*52+6 = 110 Emails were received.
Check. 52 + 110 = 162. ! Correct!
Solved.
Answer by greenestamps(13198)  (Show Source):
You can put this solution on YOUR website!
???!!!
Did the wording of the problem get changed? What I see says the number of emails received was 6 more than THREE times the number sent; two other tutors have both answered the question reading it as 6 more than TWO times the number sent.....
If it is three and not two, then....
x = number sent
3x+6 = number received
x+3x+6 = 162
4x+6 = 162
4x = 156
x = 39
3x+6 = 123
39 emails sent; 123 received; total 162
Answer by MathTherapy(10551)  (Show Source):
You can put this solution on YOUR website!
I need help breaking this down, please, and thank you.
In a certain year, the average e-mail user sent or received 162 e-mails each day. The number of e-mails received was 6 more than thrice the number sent. How many were sent and how many were received each day?
For each day,
___e-mails were sent and
___e-mails were received.
THRICE, not TWICE, so 
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