SOLUTION: Find each: The sum of two numbers is s; m times their sums is equal to n times their difference. a and c = the numbers. a + c = s a + c = ms = a - c = n Not sure how

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Question 1125362: Find each:
The sum of two numbers is s; m times their sums is equal to n times their difference.
a and c = the numbers.
a + c = s
a + c = ms = a - c = n
Not sure how to continue. Non - homework.
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
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The sum of two numbers is s; m times their sums is equal to n times their difference.
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system%28x%2By=s%2Cm%2As=n%28y-x%29%29

system%28x%2By=s%2Cm%28x%2By%29=n%28y-x%29%29

mx%2Bmy=-nx%2Bny
mx%2Bnx%2Bmy-ny=0
%28m%2Bn%29x%2B%28m-n%29y=0

system%28%28m%2Bn%29x%2B%28m-n%29y=0%2Cx%2By=s%29


Try eliminating y to find x.
system%28%28m%2Bn%29x%2B%28m-n%29y=0%2C%28m-n%29x%2B%28m-n%29y=s%28m-n%29%29

system%28%28m%2Bn%29x%2B%28m-n%29y=0%2C%28m-n%29x%2B%28m-n%29y=sm-sn%29

%28m%2Bn%29x-%28m-n%29x=-sm%2Bsn
mx%2Bnx-mx%2Bnx=sn-sm
2nx=sn-sm
highlight%28x=%28sn-sm%29%2F%282n%29%29---------that's one of them.

You can choose how you want to find y. Either choose elimination again, or try substitution to solve for y.