Question 1125346: The length of a rectangle is 15 cm more than its width (w). A blue rectangle, which is 5 cm wider and 2 cm shorter than the red one, has a perimeter 72 cm. Make a sketch of the rectangles expressing all dimensions in terms of (w). Then find the dimensions of each rectangle.
I got this straight out of my textbook and I attempted to solve it, I got the red rectangle right but I didn't for the blue one.
Found 2 solutions by solver91311, josgarithmetic:
Answer by solver91311(24713)   (Show Source):
Answer by josgarithmetic(39618)  (Show Source):
You can put this solution on YOUR website! The drawing you could (and must) do yourself.
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The length of a RED rectangle is 15 cm more than its width (w). A blue rectangle, which is 5 cm wider and 2 cm shorter than the red one, has a perimeter 72 cm. Make a sketch of the rectangles expressing all dimensions in terms of (w). Then find the dimensions of each rectangle.
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Red Rectangle
Length w+15
Width w
Blue Rectangle
Length, w+15-2=w+13
Width, w+5
Perimeter, 72
Simplify and solve this equation for w. Once done, you can evaluate the dimensions for the Red rectangle and for the Blue rectangle.
(drawing the figures will help you see the situation more clearly.)
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