SOLUTION: Find three consecutive integers such that the product of the first integer and the second integer is 42.

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Question 112527: Find three consecutive integers such that the product of the first integer and the second integer is 42.
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
X X+1 X+2 ARE THE 3 NUMBERS.
X(X+1)=42
X^2+X-42=0
(X+7)(X-6)=0
X+7=0
X=-7 ANSWER FOR THE FIRST NUMBER. -7+1=-6 IS THE SECOND NUMBER.-7+2=-5 IS THE THIRD NUMBER.
X-6=0
X=6 ANSWER FOR THE FIRST NUMBER. 6+1=7 FOR THE SECOND. 6+2=8 FOR THE THIRD.
-7*-6=42
42=42
6*7=42
42=42