SOLUTION: twice the larger of two consecutive integers is equal to fifteen less than three times the smaller

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: twice the larger of two consecutive integers is equal to fifteen less than three times the smaller       Log On


   

Question 1125068: twice the larger of two consecutive integers is equal to fifteen less than three times the smaller

Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
2%28n%2B1%29=3n-15
-
2n%2B2=3n-15
2%2B15=n
n=17

The two numbers are 17 and 18.

Answer by ikleyn(52802) About Me  (Show Source):
You can put this solution on YOUR website!
.
Let the two consecutive integers be n and (n+1).


Then the condition gives you an equation


2*(n+1) = 3n - 15.


2n + 2 = 3n - 15.


Add 15 to both sides.


2n + 2 + 15 = 3n.


Subtract 2n from both sides


2 + 15 = 3n - 2n,


17 = n.


Answer.  the two integers are  17  and  18.

You may check it on your own (and it is a good practice to do for every problem you solve) that the conditions of the problem are satisfied.