SOLUTION: If you double the first of 3 consecutive integers and add to twice the 2nd, you get the same result as you get when you triple the third and subtract 5. What are the integers?

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Let the integers be


    n, (n+1),  and  (n+2).


Then your equation is


    2n + 2*(n+1) = 3*(n+2) - 5.


Now simplify and solve for n.