SOLUTION: You need a 65% alcohol solution. On hand, you have a 385 mL of a 60% alcohol mixture. How much pure alcohol will you need to add to obtain the desired solution?

Algebra ->  Length-and-distance -> SOLUTION: You need a 65% alcohol solution. On hand, you have a 385 mL of a 60% alcohol mixture. How much pure alcohol will you need to add to obtain the desired solution?       Log On


   



Question 1124800: You need a 65% alcohol solution. On hand, you have a 385 mL of a 60% alcohol mixture. How much pure alcohol will you need to add to obtain the desired solution?

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = ml of pure alcohol needed
+.6%2A385+=+231+ ml of alcohol in 60% mixture
—————
+%28+x+%2B+231+%29+%2F+%28+x+%2B+385+%29+=+.65+
+x+%2B+231+=+.65%2A%28+x+%2B+385+%29+
+x+%2B+231+=+.65x+%2B+250.25+
+.35x+=+19.25+
+x+=+55+
55 ml of pure alcohol are needed
Check:
+%28+55+%2B+231+%29+%2F+%28+55+%2B+385+%29+=+.65+
+286+%2F+440+=+.65+
+.65+=+.65+
OK