SOLUTION: Stacy rides her bike then the bus and finally the train to visit her uncle. She rides her bike at 14 mph. The bus travels at 42 mph while the train carries her at 105 mph. She ride

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Question 1124612: Stacy rides her bike then the bus and finally the train to visit her uncle. She rides her bike at 14 mph. The bus travels at 42 mph while the train carries her at 105 mph. She rides the train for 1 hour 6 minutes longer than she rides the bus. She traveled 371 miles in 6 hours 36 minutes. How long was she riding her bike and reading on the bus?

Found 2 solutions by Boreal, josgarithmetic:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
6.6 hours total
bus=x hours
train=x+1.1
bicycle=6.6-2x-1.1=5.5-2x
Distance is 14(5.5-2x)+42x+105(x+1.1)=371
77-28x+42x+105x+115.5=371
119x+192.5=371
119x=178.5
x=1.5 hours on the bus or 63 miles
x+1.1=2.6 hours on the train or 273 miles
2.5 hours left for the bicycle or 35 miles
They add to 371 miles

Answer by josgarithmetic(39615) About Me  (Show Source):
You can put this solution on YOUR website!
               SPEED      TIME         DISTANCE
BIKE             14
BUS              42           y
TRAIN           105        y+1.1
Total Travel               6.6            371

The time on bike can be found from the total time and the other two time expressions. Bike time, 5.5-2y.

Missing distance expressions can be filled-in:
               SPEED      TIME         DISTANCE
BIKE             14        5.5-2y     14(5.5-2y)
BUS              42           y       42y
TRAIN           105        y+1.1      105(y+1.1)
Total Travel               6.6            371

Solve this equation in the one variable, y, the time while riding on the bus:
14%285.5-2y%29%2B42y%2B105%28y%2B1.1%29=371