SOLUTION: Nina rides her bike then the bus and finally the train to visit her brother. She rides her bike at 10 mph. The bus travels at 26 mph while the train carries her at 74 mph. She ride

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Question 1124610: Nina rides her bike then the bus and finally the train to visit her brother. She rides her bike at 10 mph. The bus travels at 26 mph while the train carries her at 74 mph. She rides the train for 2 hours less than she rides the bus. She traveled 115 miles in 4 hours 18 minutes. How long was she riding her bike and reading on the bus?
Answer by josgarithmetic(39615) About Me  (Show Source):
You can put this solution on YOUR website!
           SPEED       TIME         DISTANCE
BIKE          10   
BUS           26          y
TRAIN         74        y-2
Total                    4.3           115


(1) Find expression for the missing bike time.
(2) Fill the distance expressions.
(3) Make equation for the sum of the travel time. Basic Idea, RT=D. 

           SPEED       TIME         DISTANCE
BIKE          10       6.3-2y       10(6.3-2y)
BUS           26          y         26y
TRAIN         74        y-2         74(y-2)
Total                    4.3           115

10%286.3-2y%29%2B26y%2B74%28y-2%29=115
Solve that.

The question is asking for 6.3-2y and y.

"Reading" on the bus?
Should that be "Riding" on the bus?