SOLUTION: \left(\frac{3x}{2x^2y^2}\right)^{-1}\ \left(\frac{y^3}{2x}\right)^2

Algebra ->  Exponents -> SOLUTION: \left(\frac{3x}{2x^2y^2}\right)^{-1}\ \left(\frac{y^3}{2x}\right)^2      Log On


   



Question 1124601: \left(\frac{3x}{2x^2y^2}\right)^{-1}\ \left(\frac{y^3}{2x}\right)^2
Answer by ikleyn(52847) About Me  (Show Source):
You can put this solution on YOUR website!
.
As it came to the forum,  it was  UNREADABLE.

Use the plain text format :  it is the only format acceptable for the posts at this forum.

Plain text format,  .txt.

Also  REMEMBER :

    Each post must go with a question.

    The posts without questions are subject of ignoring.

    It is THE RULE, THE POLICY and the REQUIREMENT of this forum.


With it,  You are  WELCOME !