SOLUTION: The following table describes the results of roadworthiness tests of Ford Focus cars that are three years old​ (based on data from the Department of​ Transportation). T

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Question 1124594: The following table describes the results of roadworthiness tests of Ford Focus cars that are three years old​ (based on data from the Department of​ Transportation). The random variable x represents the number of cars that failed among six that were tested for roadworthiness. Find the probability of getting three or more cars that fail among six cars tested.
x P(x)
​0 0.377
1 0.399
2 0.176
3 0.041
4 0.005
5 0+
6 0+

Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
Three or more failures would be 0.041+0.005=0.046.
The "0+" actually adds 0.002 more to the number, since the sum of the numbers is 0.998, so make 0.048 as the probability.