SOLUTION: Two planes left the same airport traveling in opposite directions. The first plane left at 9:00 a.m. and 2.25 hours later, the two planes were 1825 miles apart. The second plane le
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Question 1124549: Two planes left the same airport traveling in opposite directions. The first plane left at 9:00 a.m. and 2.25 hours later, the two planes were 1825 miles apart. The second plane left at 10:00 a.m. and its average rate was 108 miles per hour slower than the first plane's average rate. Let x represent the first plane's average rate.
What was the first plane's average rate?
Enter an equation that can be used to solve this problem in the first box.
Solve for x and enter the first plane's average rate in the second box. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! distance= velocity * time
so for plane 1, the distance is 2.25x
for the second, the distance is 1.25(x-108)
that sum is 1825
2.25x+1.25x-135=1825
3.5x=1960
x=560 mph speed of first plane (average) ANSWER
x-108=452 mph of second
The first hour they are 560 miles apart, and hour and a quarter left, the first plane goes 700 miles and the second 565. Those three numbers add to 1825.
