SOLUTION: I am trying to solve for x in the following equation but cant seem to get it right. please see below what i have so far. Can you please tell me where I went wrong. Thank you so muc

Algebra ->  Equations -> SOLUTION: I am trying to solve for x in the following equation but cant seem to get it right. please see below what i have so far. Can you please tell me where I went wrong. Thank you so muc      Log On


   

Question 112434: I am trying to solve for x in the following equation but cant seem to get it right. please see below what i have so far. Can you please tell me where I went wrong. Thank you so much!!!!
4x^2-4x-3=0
4x^2-4x+3-3=0+3
4x^2-4x=3
(4x+2)(4x-2)-4x=3
-4x=3
-4x/-4=3/-4
x=.75
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
4x%5E2-4x-3=0
4x%5E2-4x%2B3-3=0%2B3
4x%5E2-4x=3
%284x%2B2%29%284x-2%29-4x=3This step is wrong because %284x%2B2%29%284x-2%29=16x%5E2-4
Also, if you plug your answer into the original equation it should work.
4x%5E2-4x-3=0
4%283%2F4%29%5E2-4%283%2F4%29-3=0
9%2F4-4-3=0
9%2F4-7=0
9%2F4-28%2F4=0
-37%2F4=0
Since your solution leads to a false statement, it's not a good solution.
Use the quadratic formula with your original equation to get the solution.
4x%5E2-4x-3=0
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
Where
a=4
b=-4
c=-3
Therefore
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x+=+%284+%2B-+sqrt%28+%28-4%29%5E2-4%2A4%2A%28-3%29+%29%29%2F%282%2A4%29+
x+=+%284+%2B-+sqrt%28+16%2B48%29%29%2F%288%29+
x+=+%284+%2B-+sqrt%28+64%29%29%2F%288%29+
x+=+%284+%2B-+8+%29%2F%288%29+
x+=+%284+%2B+8+%29%2F%288%29+
x+=+%2812%29%2F%288%29+
x+=+3%2F2+
and
x+=+%284+-+8+%29%2F%288%29+
x+=+%28-4+%29%2F%288%29+
x+=+-%281%2F2%29+
Let's check the answers.
4x%5E2-4x-3=0
4%283%2F2%29%5E2-4%283%2F2%29-3=0
4%289%2F4%29-6-3=0
9-6-3=0
0=0
True statement.
4x%5E2-4x-3=0
4%28-1%2F2%29%5E2-4%28-1%2F2%29-3=0
4%281%2F4%29%2B2-3=0
1%2B2-3=0
0=0
True statement.
Good solutions.