SOLUTION: Mang Gustin can climb a coconut tree at the rate of 10 ft. per minute and return at 20 ft.per minute. If it took him 3 minutes to climb and return, what is the height of the coconu
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Question 1123958: Mang Gustin can climb a coconut tree at the rate of 10 ft. per minute and return at 20 ft.per minute. If it took him 3 minutes to climb and return, what is the height of the coconut tree?
Let H be the height of the tree, in feet.
Then is the time to climb the tree, while is the time to return.
The total time is the sum + , and your equation is
+ = 3 minutes.
To solve it, multiply both sides of the equation by 20. You will get
2H + H = 60,
3H = 60 ====> H = 60/3 = 20.
Answer. The height of the tree is 20 ft.
Check. The time to climb is 20/10 = 2 minutes.
The time to return is 20/20 = 1 minute.
2 + 1 = 3 minutes. ! Correct !
You can put this solution on YOUR website! Let = time in minutes to go up the tree = time in minutes to go down the tree
Let = the height of the tree in feet
——————————-
Equation for going up:
(1)
Equation for going down:
(2)
—————————————
By substitution:
(2)
(2)
(2)
(2)
And
(1)
(1)
The tree is 20 ft high
——————————-
Check:
(2)
(2)
OK
