SOLUTION: solve the simultaneous equation: 1.) log2^x - log2^y =2, log2^(x-2y) =3

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Question 1123813: solve the simultaneous equation:
1.) log2^x - log2^y =2, log2^(x-2y) =3
Found 2 solutions by Alex.33, MathTherapy:
Answer by Alex.33(110) About Me  (Show Source):
You can put this solution on YOUR website!
Assume that 2 s are the bases of the log, not contained in the expressions.
(If not please resubmit the qustion with the base specified, in case a bare log x can be recognized to be base e or 10)
log%282%2C+x%2Fy%29=2%2C+log%282%2C+x-2y%29=3
x%2Fy=4
x-2y=8
4y-2y=8
y=4
x=16
Hope this solves your problem. Thanks!

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

solve the simultaneous equation:
1.) log2^x - log2^y =2, log2^(x-2y) = 3 
If it's , then highlight_green%28matrix%281%2C7%2C+x%2C+%22=%22%2C+16%2C+and%2C+y%2C+%22=%22%2C+4%29%29. 

If not, you're on your own!