SOLUTION: Susan invests 3 times as much money at 11% as she does at 7%. If her total interest after 1 year is $1600, how much does she have invested at each rate? ___ at 7% and ___at 11%

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: Susan invests 3 times as much money at 11% as she does at 7%. If her total interest after 1 year is $1600, how much does she have invested at each rate? ___ at 7% and ___at 11%      Log On

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Question 1123789: Susan invests 3 times as much money at 11% as she does at 7%. If her total interest after 1 year is $1600, how much does she have invested at each rate?
___ at 7% and ___at 11%

Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
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Let x be the amount Susan invested at 7%.

Then the amount invested at 11% is 3x dollars.


Your equation is


    0.07x + 0.11*(3x) = 1600.


    0.07x + 0.33x = 1600


    0.4x = 1600  ====>  x = 1600%2F0.4 = 4000 dolars.


Answer.  $4000  at  7%  and  $12000  at 11%.


Check.   0.07*4000 + 0.11*12000 = 1600 dollars.    ! Correct !

Solved.