You can put this solution on YOUR website! p(x)= (-1/2)x^3 - x^2 + 4x
To find the zeros factor and set = 0:
x((-1/2)x^2 - x + 4) = 0
x = 0 is a solution
The quadratic can be factored as:
[multiply through by -2] (x + 4)(x - 2) = 0
This gives x = 2, x = -4
So the zeros are: -4,0,2
Not sure what is meant by graph y > p(x)