SOLUTION: The ratio of the piece of house was16:23.two yrs later when the price of the first had risen by 10% and that of the second by gh477,the ratio of their prices become 11:20.find the

Algebra ->  Finance -> SOLUTION: The ratio of the piece of house was16:23.two yrs later when the price of the first had risen by 10% and that of the second by gh477,the ratio of their prices become 11:20.find the       Log On


   

Question 1123628: The ratio of the piece of house was16:23.two yrs later when the price of the first had risen by 10% and that of the second by gh477,the ratio of their prices become 11:20.find the original price of the two houses.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
The way I understand this:
The ratio of the price of two houses was 16:23.
two yrs later when the price of the first had risen by 10% and that of the second by gh477,
the ratio of their prices become 11:20.
find the original price of the two houses.
:
let x = the multiplier
then
16x = original price of the 1st house
and
23x = original price of the 2nd
:
Two years later;
1.1(16x) = 17.6x; the price of the 1st house
and
(23x+477) = the price of the 2nd house
:
The ratio now is 11:20
%2817.6x%29%2F%2823x%2B477%29 = 11%2F20
cross multiply
20(17.6x) = 11(23x+477)
352x = 253x + 5247
352x - 253x = 5247
99x = 5247
x = 5247/99
x = 53 is the multiplier
therefore
53*16 = gh848 is the original price of the 1st house.
and
53*23 = gh1219 is the price of the 2nd house.

: