SOLUTION: Carla and patrick rode stationary bikes for the same smoking of time. Carla rode at 8 miles per hour, and patrick rode at 4.5 miles per hour. If carla rode 2.63 miles farther than

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Question 1123610: Carla and patrick rode stationary bikes for the same smoking of time. Carla rode at 8 miles per hour, and patrick rode at 4.5 miles per hour. If carla rode 2.63 miles farther than patrick. How Long did they use the bikes?

i cant solve it trying to figure out what order should i put it

Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39628) About Me  (Show Source):
You can put this solution on YOUR website!
?
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Carla rode at 8 miles per hour, and patrick rode at 4.5 miles per hour. If carla rode 2.63 miles farther than patrick. How Long did they use the bikes?
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Each rode for the same time? DURING the same time?
              SPEED       TIME       DISTANCE

CARLA           8          x           d+2.63

PATRRICK        4.5        x            d

%28d%2B2.63%29%2F8=d%2F4.5
Solve this for d.

Use value found for d to find x.
x=d%2F4.5



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(not the only way)

Answer by ikleyn(52867) About Me  (Show Source):
You can put this solution on YOUR website!
.
Carla and Patrick rode highlight%28cross%28stationary%29%29 their bikes for the same highlight%28cross%28smoking%29%29 amount of time.
Carla rode at 8 miles per hour, and Patrick rode at 4.5 miles per hour.
If Carla rode 2.63 miles farther than Patrick, how Long did they use the bikes?
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Pay attention on how I edited your post in order for it makes sense.


Your equation is THIS :


Distance Carla rode - distance Patrick rode = 2.63 mile,     or


8*t                 - 4.5t                  = 2.63


where t = "How Long did they use the bikes"  is the unknown amount of time under the question.


8t -4.5t = 2.63


3.5t = 2.63


t = 2.63%2F3.5 = 0.751429 hours.