SOLUTION: A pile of 34 coins is worth $5.10. There are two nickels and the remainder are quarter and dimes. How many quarter and dimes are there?

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Question 1123487: A pile of 34 coins is worth $5.10. There are two nickels and the remainder are quarter and dimes. How many quarter and dimes are there?
Answer by ikleyn(52803)   (Show Source):
You can put this solution on YOUR website!
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The equivalent formulation is

32 coins, all nickels and/or dimes, $5.00

It is a standard coin problem.

25Q + 10*(32-Q) = 500 cents ("money" equation) Simplify and solve for Q, which is the number of quarters. Answer. Q = = 12. Dimes = 32 - 12 = 20.

Solved.

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On coin problems, see the lessons
    - Coin problems
    - More Coin problems
    - Solving coin problems without using equations
    - Kevin and Randy Muise have a jar containing coins
    - Typical coin problems from the archive
    - Three methods for solving standard (typical) coin word problems
    - More complicated coin problems
    - Solving coin problems mentally by grouping without using equations
    - Santa Claus helps solving coin problem
    - OVERVIEW of lessons on coin word problems
in this site.

You will find there the lessons for all levels - from introductory to advanced,
and for all methods used - from one equation to two equations and even without equations.

Read them and become an expert in solution of coin problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Coin problems".

Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.