SOLUTION: Log2(12x-10)=1+log2(4x+3)

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Question 1123393: Log2(12x-10)=1+log2(4x+3)
Answer by jerryguo41(197) About Me  (Show Source):
You can put this solution on YOUR website!
log2%2812x-10%29=1%2Blog2%284x%2B3%29
1. Use Log Rule a+=+logb%28b%5Ea%29
log2%2812x-10%29=log2%282%5E1%29%2Blog2%284x%2B3%29
2. Use Log Rule logc%28a%29%2Blogc%28b%29=logc%28a%2Ab%29
log2%2812x-10%29=log2%282%2A%284x%2B3%29%29
log2%2812x-10%29=log2%288x%2B6%29
3. Same Base logc%28f%28x%29%29=logc%28g%28x%29%29 => f%28x%29=g%28x%29
12x-10=8x%2B6
4. Solve for x
12x-8x=6%2B10
4x=16
x=4