SOLUTION: The length of a rectangle is 2 meters less than 2 times the width. The perimeter is 20 meters. Find the width.

Algebra ->  Parallelograms -> SOLUTION: The length of a rectangle is 2 meters less than 2 times the width. The perimeter is 20 meters. Find the width.       Log On


   

Question 1123324: The length of a rectangle is
2
meters less than
2
times the width. The perimeter is
20
meters. Find the width.
Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
.
We know that 


L + W = 10    <<<---===  10 = 20%2F2, half of the perimeter.


We also know that  L = 2W - 2.   Substitute it into very first equation. You will get


(2W-2) + W = 10,   or


2W - 2 + W = 10,

3W = 10 + 2 = 12  ====>  W = 12/3 = 4.


Answer.  The width is 4 meters.

Solved.