SOLUTION: the sides of a rectangle B are 20% greater than the sides of rectangle A. rectangle B's area is what percent greater than that of rectangle A?

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Question 1123323: the sides of a rectangle B are 20% greater than the sides of rectangle A. rectangle B's area is what percent greater than that of rectangle A?
Answer by josgarithmetic(39618) About Me  (Show Source):
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Rectangle B
sides 1.2w and 1.2L
area 1.2^2*wL

Rectangle A
sides w and L
area wL


%281.2%5E2-1%29%2A100-----the percent that area B is greater than area A
44%