SOLUTION: Kathryn started biking to the study group traveling 10 mph, after some time the bike got a flat so Kathryn walked the rest of the way, traveling 3 mph. If the total trip to the stu
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Question 1123152: Kathryn started biking to the study group traveling 10 mph, after some time the bike got a flat so Kathryn walked the rest of the way, traveling 3 mph. If the total trip to the study group took 9 hours and it was 55 miles away, how long did Kathryn travel at each speed? Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39616) (Show Source):
Let t be the time she biked.
The she walked for (9-t) hours.
The total distance is
10t + 3*(9-t) = 55
10t + 27 - 3t = 55
7t = 55 - 27 = 28
t = 28/7 = 4.
Answer. She biked 4 hours and walked 9-4 = 5 hours.
Check. 1)10*4 + 3*5 = 55 miles. ! Correct !