SOLUTION: Cody left the park traveling 12 mph. Then, 2 hours later, Jeff left traveling the same direction at 18 mph. How long until Jeff catches up with Cody?
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Question 1123150: Cody left the park traveling 12 mph. Then, 2 hours later, Jeff left traveling the same direction at 18 mph. How long until Jeff catches up with Cody? Answer by ikleyn(52793) (Show Source):
Let "t" be the time after Jeff left the park.
The the time after Cody left the park is (t+2) hours.
Jeff traveled the distance of 18*t miles.
Cody traveled 12*(t+2) miles.
At the moment Jeff catches up with Cody, they cover the same distance.
It gives you an equation
18t = 12(t+2).
18t = 12t + 24,
18t - 12t = 24
6t = 24
t = 24/6 = 4 hours.
Answer. 4 hours.
