SOLUTION: In a sample of 80 adults, 28 said that they would buy a car from a friend. Three adults are selected at random without replacement. Find the probability that none of the three woul

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Question 1123139: In a sample of 80 adults, 28 said that they would buy a car from a friend. Three adults are selected at random without replacement. Find the probability that none of the three would buy a car from a friend.
Found 2 solutions by ikleyn, rothauserc:
Answer by ikleyn(52765) About Me  (Show Source):
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There are  C%5B80%5D%5E3 = %2880%2A79%2A78%29%2F%281%2A2%2A3%29 = 82160 different ways to select three persons of 80.


If none of the three would buy a car from the friend, it means that all three are from the subset of 80-28 = 52 persons.


There are  C%5B52%5D%5E3 = %2852%2A51%2A50%29%2F%281%2A2%2A3%29 = 22100 different ways to select three persons of 52.


The probability under the question is the ratio of these two integers:


    P = 22100%2F82160 = 0.2690 = 26.90%  (approximately).

Solved.



Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
80 - 28 = 52 would not buy a car from a friend
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Probability that 3 adults selected without replacement would not buy a car from a friend = (52/80) * (51/79) * (50/78) = 0.2689 is approximately 0.269
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