SOLUTION: Mary has a hamburger stand in town. She says there is a linear relationship between the price (p) of hamburgers and the number sold (x) i.e. &#119961;=&#119938;&#119953;+&#119939;.

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Question 1123071: Mary has a hamburger stand in town. She says there is a linear relationship between the price (p) of hamburgers and the number sold (x) i.e. 𝒙=𝒂𝒑+𝒃. At N$10 she sells 1360 hamburgers per month, but only 510 when she doubles the price.
(a) Find a and b
(b) How many hamburgers will be sold at N$16?
(c) What price will ensure sales of 1020 hamburgers?
(d) What is the maximum possible price?
Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website!

You are given 2 points on a straight line, ( p,x )
This is the order because x depends on p
( 10, 1360 )
( 20, 510 )

and

��
By subtraction:

And

The equation is:

��-
At

will be sold
��-
At

N$14
��-
The max price will result in 0 sold, so

N$26 is maximum price

SOLUTION: Mary has a hamburger stand in town. She says there is a linear relationship between the price (p) of hamburgers and the number sold (x) i.e. &#119961;=&#119938;&#119953;+&#119939;.

SOLUTION: Mary has a hamburger stand in town. She says there is a linear relationship between the price (p) of hamburgers and the number sold (x) i.e. 𝒙=𝒂𝒑+𝒃.