SOLUTION: if a projectile is fired straight upward from the ground with an initial speed of 40 ft per second,neglecting air resistance,its height s (in feet) above t seconds after projection

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Question 1123040: if a projectile is fired straight upward from the ground with an initial speed of 40 ft per second,neglecting air resistance,its height s (in feet) above t seconds after projection is given by s=-16t^2+40t. which equation should be used to determine the time at which the height of the projectile reaches 40ft?
Answer by ikleyn(52788) About Me  (Show Source):
You can put this solution on YOUR website!
.
The equation you are asking for is


s(t) = 40,   or


-16t^2 + 40t = 40.


But the problem is that this equation has NO real solutions, and maximal height of the projectile is only 25 ft, so it will NEVER reach 40 ft height.



graph%28+330%2C+330%2C+-2%2C+5%2C+-5%2C+50%2C%0D%0A++++++++++-16x%5E2%2B40x%0D%0A%29


Plot s(t) = -16t%5E2+%2B+40t 


Who gave you this fake problem ?

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In this site, there is a bunch of lessons on a projectile thrown/shot/launched vertically up
    - Problem on a projectile moving vertically up and down
    - Problem on an arrow shot vertically upward
    - Problem on a ball thrown vertically up from the top of a tower
    - Problem on a toy rocket launched vertically up from a tall platform

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook under the topic "Projectiles launched/thrown and moving vertically up and dawn".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.