SOLUTION: The sum of consecutive integers 1, 2, 3, n is given by the formula 1/2n(n+1) how many consecutive integers starting with 1 must be added to get a sum of 1225 The integers 1 th

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Question 1122813: The sum of consecutive integers 1, 2, 3, n is given by the formula 1/2n(n+1)
how many consecutive integers starting with 1 must be added to get a sum of 1225
The integers 1 through ? Need to be added yo get a sum of 1225
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+%281%2F2%29%2An%2A%28+n%2B1+%29+=+1225+
+n%2A%28+n%2B1%29+=+2450+
+n%5E2+%2B+n+-+2450+=+0+
+%28+n+-+49+%29%2A%28+n+%2B+50+%29+=+0+
+n+=+49+
1225 is the sum from 1 to 49
( I actually checked this on my calculator )