SOLUTION: Find three consecutive even integers such that the sum of the squares of the first two is four less than twice the square of the third.

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Question 1122798: Find three consecutive even integers such that the sum of the squares of the first two is four less than twice the square of the third.
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
x, x+2, and x+4
x^2+x^2+4x+4+4=2(x^2+8x+16)
2x^2+4x+8=2x^2+16x+32
-24=12x
x=-2
-2, 0, 2
sum of squares of first two is 4, and that is 4 less than twice the square of the third, which would be 8.