Question 1122755: A woman bought oranges at $1.44 a dozen. She sold 4/5 of them at the rate of 4 for 60 cents and the rest at the rate of 2 for 25 cents. She gained $5.00 in yhe transaction. How many oranges did she buy?
Thank you for help. I really appreciate it.
Found 2 solutions by Boreal, greenestamps:
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! x is the number she bought
the oranges are 12 cents or $0.12 each, since there are 12 in a dozen.
(4/5) of them were sold for 15 cents each (4 for 60 cents) and the rest at 12.5 cents each (2 for 25 cents).
She gained $5.00
That means she had to make $5.00 (profit)+0.12x, the cost she paid for the oranges.
therefore,
5.00+0.12x=.80x(0.15x)+.20x(0.125)
5.00+0.12x=0.12x+0.0250x
5.00=0.0250x
x=200 oranges or 16 dozen 8. Assuming she can buy part of a dozen at the same cost, she paid $24 for the oranges and needed to make $29 overall.
She sold 160 oranges, 4/5, at 15 cents each for $24. She sold 40 for 12.5 cents each for $5.
200 oranges ANSWER
Answer by greenestamps(13200)  (Show Source):
You can put this solution on YOUR website!
The purchase price is $1.44 per dozen, or 12 cents each.
She sold 4/5 of them at 4 for 60 cents, a rate of 15 cents each; she sold 1/5 of them at 2 for 25 cents, a rate of 12.5 cents each.
Let x be the number she bought. Then write and solve the equation that says
4/5 of the oranges at 15 cents each, plus 1/5 of them at 12.5 cents each, is $5.00 (500 cents) more than all the oranges at 12 cents each:
You can finish from there....
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