SOLUTION: find three consecutive even integers such that four times of first integer is 10 more than the sum of second and third integer.

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Question 1122666: find three consecutive even integers such that four times of first integer is 10 more than the sum of second and third integer.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let the unknown even integers be
n, n+2, n+4
+4n+=+n+%2B+2+%2B+n+%2B+4+%2B+10+
+4n+=+2n+%2B+16+
+2n+=+16+
+n+=+8+
The even integers are 8, 10, 12
Check:
+4%2A8+=+10+%2B+12+%2B+10+
+32+=+32+
OK