SOLUTION: Ada takes twice as much time as Alice to complete a work and Hope does it in the same time as Ada and Alice together. If all three working together can finish the work in 6 days, t

Algebra ->  Numeric Fractions Calculators, Lesson and Practice -> SOLUTION: Ada takes twice as much time as Alice to complete a work and Hope does it in the same time as Ada and Alice together. If all three working together can finish the work in 6 days, t      Log On


   



Question 1122657: Ada takes twice as much time as Alice to complete a work and Hope does it in the same time as Ada and Alice together. If all three working together can finish the work in 6 days, then the time taken by each of them to complete the job is?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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Ada takes twice as much time as Alice to complete a work
let a = time required by Alice to complete the work
then
2a = time required by Ada
and
Hope does it in the same time as Ada and Alice together.
h = a + 2a
h = 3a
If all three working together can finish the work in 6 days,
let the completed job = 1
6%2Fa + 6%2F%282a%29 + 6%2F%283a%29 = 1
multiply equation by 6a, cancel the denominators
6(6) + 3(6) + 2(6) = 6a
36 + 18 + 12 = 6a
66 = 6a
a = 11 days, Alice alone
2a = 22 days, Ada alone
3a = 33 days Hope alone