SOLUTION: mathematical expression for a three-digit number whose hundred digits is half the tens digit and the tens digit is 2 more than the units digit
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Question 1122469: mathematical expression for a three-digit number whose hundred digits is half the tens digit and the tens digit is 2 more than the units digit Found 2 solutions by solver91311, greenestamps:Answer by solver91311(24713) (Show Source):
Let x be the hundreds digit;
then the tens digit is 2x (the tens digit is twice the hundreds digit);
then the units digit is 2x-2 (it is 2 less than the tens digit)
The value of the 3-digit number ABC is 100A+10B+C. So an expression for the 3-digit number in this problem is
100(x)+10(2x)+1(2x-2)
Simplify if required....
Note that x and 2x are both single-digit positive integers; that means x can have only the values 1, 2, 3, or 4.
Those values of x in the expression shown will produce all of the 3-digit numbers that satisfy the conditions of the problem.
120
242
364
486
Another completely different way to solve the problem is to make a list of the 3-digit numbers that satisfy the given conditions and find an algebraic expression that produces exactly that list.
Making the list is relatively easy; choose a hundreds digit; then the tens digit is twice the hundreds digit; then the units digit is 2 less than the tens digit:
The 3-digit numbers satisfying the given conditions are
120, 242, 364, and 486.
A bit of simple algebra, seeing the first number 120 and a common difference of 122 between successive numbers in the list, yields the linear expression
122x-2
which is the simplified form of the expression shown above.