SOLUTION: Solve, for x, the equation log base 2 (5x^2-x-2) = 2+2 log base 2 of x Thanks so much!
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Question 112246
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Solve, for x, the equation log base 2 (5x^2-x-2) = 2+2 log base 2 of x
Thanks so much!
Answer by
scott8148(6628)
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using rules of logarithms; 5x^2-x-2=4x^2
x^2-x-2=0 ___ (x+1)(x-2)=0
remember, logarithms are NOT defined for negative numbers