SOLUTION: How much 36% acid solution should be added to 8% acid solution to make 224 mL of a 10% acid solution?

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: How much 36% acid solution should be added to 8% acid solution to make 224 mL of a 10% acid solution?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1122296: How much 36% acid solution should be added to 8% acid solution to make 224 mL of a 10% acid solution?
Answer by josgarithmetic(39623) About Me  (Show Source):
You can put this solution on YOUR website!
x, volume of 36% acid
224-x, volume of 8% acid

This equation is to account for the amount of pure 100% acid: 36x%2B8%28224-x%29=10%2A224

If divide both sides by 4,
9x%2B2%28224-x%29=10%2A56

Simplify and solve for x.
9x%2B448-2x=560
7x=560-448
7x=112
x=16---------volume of the 36% acid to use

208----------volume of the 8% acid to use

(the results should be rechecked)